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Electron and Proton Atomic Energy - Assignment Example

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This paper 'Electron and Proton Atomic Energy ' tells that A coil is wound on an iron core and our task is to find its self-inductance. During an experiment, the current in the primary coil is increased from 1.7 to 3.7A in 0.02 seconds. In the process, it induced an emf of 4 volts…
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Electron and Proton Atomic Energy
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  • The Relationship between B and I for a wire-carrying current is electromagnetic interaction due to associating elementary particles. Direct Relationship
  • Relationship between B and R for a wire-carrying current Inverse Relationship
  • Ohm’s law states that the current through a conductor between two points is directly proportional to the potential difference across the two points. I=V/R
  • In Ohm’s law, I and Rare inversely proportional to each other = True
  • In Ohm’s law, V and Rare directly proportional to each other= True
  • A typical galvanometer deflects full scale (the maximum current that you can pass through it) to a draft of 0.010A, and it has a resistance of 50ohms. How can it be converted into a:
    • 5A ammeter?

V = 0.010*50 = 0.5 V

Rs =   0.5 /4.99 = 0.1002 Ω.  By connecting a shunt resistor of 0.1002 Ω in parallel.

  • 20V voltmeter?

Rt = 20 / 0.010 = 2000 Ω. By connecting a resistor of 1950 Ω in series.

  • 50V voltmeter?

Rt = 50 / 0.01 = 5000 Ω. By connecting a resistor of 4950 Ω in series.

 

  1. Exit Questions
    • What is the unit of a magnetic field? B Teslas ( T)
    • What is the company of the magnetic flux? ƟB Webers (Wb)
    • As given by Ampere’s law, the magnetic field increases the distance of the point from the wire.
    • Is there a magnetic field outside of a solenoid? No, outside the solenoid, the area is also fragile due to this cancellation effect. For a solenoid which is long compared to its diameter, the site is very close to zero.
    • What is the force's direction (up or down) on an electron moving along the positive x-axis and entering a magnetic field perpendicular to the chalkboard (going inside)? Up
    • A galvanometer is used to measure current. True
    • A voltmeter has a high internal resistance. True
    • An ammeter has a low internal resistance. True
    • An ammeter is used in parallel in an electrical circuit. False it will cause a short circuit
    • A voltmeter is used in series in an electrical circuit. True

                                                                                                 

  1. Practice Home Work
    • A typical galvanometer has resistance of 60ohms and it can detect full scale for a voltage of 120mV across its terminals. How can it be made into a 4A ammeter?

L = 0.12 / 60 = 0.002 A

Rs     = 0.12 / 3.998 = 0.030015 Ω.  By connecting a shunt resistor of 0.030015 Ω in parallel

 

  • A typical galvanometer deflects full scale of (the maximum current that you can pass through it) to a draft of 0.015A, and it has a resistance of 40Ohms. How can it be converted into a:
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